-5t^2+10+18=18t

Solution for -5t^2+10+18=18t equation:

-5t^2+10+18=18t

We move all terms to the left:

-5t^2+10+18-(18t)=0

We add all the numbers together, and all the variables

-5t^2-18t+28=0

a = -5; b = -18; c = +28;
Δ = b2-4ac
Δ = -182-4·(-5)·28
Δ = 884
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{884}=\sqrt{4*221}=\sqrt{4}*\sqrt{221}=2\sqrt{221}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{221}}{2*-5}=\frac{18-2\sqrt{221}}{-10}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{221}}{2*-5}=\frac{18+2\sqrt{221}}{-10}
$